Mechanical Engineering, Indian Institute of
Science, Bangalore 560 012, India
Optimization hinders evolution!
ME256
Variational methods and structural optimization
Jan.-May, 2011
Instructor: G. K.
Ananthasuresh, Room 106, ME Building, suresh at
mecheng.iisc.ernet.in
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Homework #1
Assigned: Jan. 6th, 2011
Due: Jan. 13th, 2011
Points: 30
Additional points for work that is beyond instructor's expectation!
Look up Homework #1 of 2010 offering of this course and the solution posted there to know what is meant by "beyond instructor's expectation".
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15 points
Minimize f = (5/x1) + (2/x2)
with respect to {x1, x2}
Subject to
g1 = x1 + x2 - 3 <= 0
g2 = 4x1 + x2 - 6 <= 0
g3 = x1 + 3x2 - 20 <= 0
-x1 <= 0 and -x2 <= 0
"<=" indicates "less than or equal to".
[From p. 249 of "Numerical Optimization Techniques for Engineering Design" by G. N. Vanderplaats, McGraw-Hill, New York, 1984]
Solve the above problem by hand and by using Matlab's fmincon routine. Draw the contours of the objective function, the curves of the constraints, and show the
feasible space in a 2D plot. Indicate the optimum in the figure. Show what paths the
algorithm takes to reach the optimum from different initial guesses.
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15 points
As shown in Fig. 1, a farmer needs to decide the boundary of his farm between the river and the three roads to enclose an area A
He wants to minimize the length of the fence
(excluding the roads) that separates his farm from the river. The animatation in Fig. 1 shows that the farmer is not able to decide the bondary curve. Help him determine the boundary curve using the following information.
- The origin is at the bottom-left corner of the green patch. Let the right edge of the left vertical road be the y-axis and the
top edge of the horizontal road be the x-axis.
- The horizontal extent between the two vertical roads (i.e., along the x-axis) of the green patch is 10 m.
- The equation of the lower boundary of the river is given by (-0.8x + 8 = y). Note that this is different from what is shown in Fig. 1.
- The farmer is allowed an area of 25 m2 (i.e., A = 25 m2).
- What changes if the farmer is allowed 35 m2 (i.e., A = 25 m2)?
Acknowledgment: The credit for posing this problem, albeing in a different context, goes to Prof. Anindya Chatterjee (currently at IIT-Kharagpur).
So, we call it "Chatterjee's problem".
Figure 1. The boundary of the farmer's green patch is to be minimised while retaining
the value of its area to be A. [Courtesy: G. Bharathi]